Falling

For anyone wondering it's because the bowling ball slightly pulls the earth faster toward itself. This amount is too small to possibly measure. But imagine if the bowling ball were the size of another Earth and it's easier to see why it happens.

Thanks for the non-jargon version
This amount is too small to possibly measure

What the fuck did you say to me you little bitch? I'm going to go get $300 million in funding to create a device so complex and so sensitive that a butterfly sneezing 30 miles away will fuck it up and then I'm going to directly measure the the acceleration of the earth as a result of the mass of that bowling ball. You fucked up, kiddo.

Average metrologist, probably
- The issue isn't so much the sensitivity (although that is a significant issue), it's all the other crap going on. You'll probably be able to filter out the Mains Hum, but every anything moving in the same axis as the test will confount the data.
  
  I'm thinking we might set up the instuments near counterweight energy storage or pumped hydro, and some on the exact opposite side of the planet, and try to measure the movement of the earth that way.
  
  We can already see a change in the length of a day after big earthquakes and dam construction/destruction, but I don't think the acceleration has ever been measured directly.
When you drop them at the same time, it doesn't matter though.
- because of two bodies can not occupy the same space, the feather and the ball will be in different position when you drop them. And therefor gravitation will pull the earth slightly more toward the ball and slightly less toward the feather.
But being more massive means that due to inertia the ball will take just a tiny little wee bit longer to start moving no? So they end up falling at the same time.

Also, are these Newtonian mechanics? How do they compare to relativity at the "bowling ball and feather" scale?

Someone please correct me if I'm wrong. It's been a while since I read anything physics-related.
- The acceleration from gravity would be the same no matter the object mass (~9.8m/s²).
- The above is just referring to the fact that the standard "feather vs. bowling ball" question assumes the earth/moon/ground is immovable. In that case, Newton says they fall the same.
  
  The fact that the ground is not immovable is what's being referenced --- in this picture, things don't "fall," they are each accelerated towards each other.

This is fascinating! Both of them accelerate toward the earth at the same rate, but because of the bowling ball's greater mass, the EARTH accelerates faster toward the bowling ball than it does toward the feather, so it's imperceptibly faster XD

But they are being dropped at the same time for dramatic effect, so the earth will also be accelerating towards the feather at bowling ball speeds because the feather is next to the bowling ball, therefore they still land at the same time.
- That’s only be true if the feather was in the same position as the ball. Otherwise, the earth is moving ever so slightly more towards the ball.
- No, because the earth is accelerating towards the bowling ball and the feather is next to the bowling ball, the force vector is (ever so slightly) greater towards the bowling ball than the feather, thus the bowling ball drops faster
Thank you.

xkcd

That's a good one. Did not know that xkcd yet.

It's not even because it's heavier, it's because it's way more dense.

It's not density, it's mass. A mass of 1kg compressed to the density of the Sun's core would pull the Earth with just as much force as a 1kg ball of styrofoam.
- And is the Sun was replaced with a black hole of the same mass, the Earth would just keep on rotating around it without issues, if slightly frozen
- Just to add some formality to this, the original commenter might want to look up the shell theorem for classical mechanics and Birkhoff's theorem for general relativity.
The guy on the right, if he be so wise in the ways of science, should be using the word "massive" instead of "heavier".
Can you explain please
- Heavy is a subjective term based on the force of gravity. You are heavier if we weigh you on the earth compared to if you are weighed on the moon.
  
  Your mass in those two examples is unchanged. The amount of mass you have is finite and not subjective like weight.
- The feather clearly has a more aerodynamic shape, thus, it wouldn't fall as fast as a sphere with the same weight.

Does the bowling ball ever so slightly increase the gravitational constant because of it's greater mass? Is that what the right guy is getting at?

No. F=GMm/d2. The mass of the earth doesn’t change so g=GM/d2 will not change
- Ah but the earth doesn't just attract the ball or feather. The bowling ball attracts the earth as well, and since it has more mass, it will pull the earth towards it faster than the feather.
  
  But if you drop them at the same time, that's moot.
- So why does the bowling ball fall faster in a vacuum? Does it appear faster locally because the heavier object makes local time slower than the lighter object compared to a distant observer? I'm trying to understand what the meme is getting at.
because of its* greater mass

I think the answer to this question changes based on your interpretation of 'falling faster'. I.e. whether that refers to the total time between the start and end of the fall or to the speed of the feather/ball to an outside observer.

There's a video of astronauts doing the heavy thing vs feather in vacuum experiment. I think it was a hammer rather than a bowling ball tho.

Since we are in avaccum

That's where you're wrong kiddo

I haven't seen anyone mention this yet, so here's how I understand it. The feather falls slower in non-vacuum conditions because it reaches its terminal velocity much more quickly than the bowling ball.

Edit: terminal velocity: https://en.m.wikipedia.org/wiki/Terminal_velocity

Also edit: https://ucscphysicsdemo.sites.ucsc.edu/physics-5a6a/coin-and-feather/#:~:text=Because the feather has a,small%2C the feather falls slowly.

How would it reach terminal velocity in a vacuum?
- I imagine terminal velocity with no air resistance would be 9.8m/s/s. I was saying that the feather reaches terminal velocity more quickly than a bowling ball in non-vacuum conditions

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