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Does the bowling ball ever so slightly increase the gravitational constant because of it's greater mass? Is that what the right guy is getting at?
No. F=GMm/d2. The mass of the earth doesn’t change so g=GM/d2 will not change
Ah but the earth doesn't just attract the ball or feather. The bowling ball attracts the earth as well, and since it has more mass, it will pull the earth towards it faster than the feather.
But if you drop them at the same time, that's moot.
In other words, the feather and ball are both attracted to the earth at the same rate but because the ball has a higher mass, the earth is very slightly more attracted to the ball
Maybe the ball is just more of their type?
So why does the bowling ball fall faster in a vacuum? Does it appear faster locally because the heavier object makes local time slower than the lighter object compared to a distant observer? I'm trying to understand what the meme is getting at.
That's the neat thing: it doesn't
I’m trying to understand as well.
Because it, ever so slightly, pulls Earth towards it with it's own, miniscule gravity.
But that doesn't make the bowling ball fall faster to a distant observer, just the earth fall twords the ball. To an observer on earth it would appear to fall faster though.
Yeah, I think the meme is intended from the perspective of an observer on Earth.
The ball's acceleration is identical to the feather's, but it's fall ends up shorter.
because of its* greater mass