Rule 2 0
I think this could use a bit more elaboration, since if x-y+y-z < -(|x-y|+|y-z|), then ||x-y|+|y-z|| >= |x-y+y-z| wouldnt be true. This is impossible though since q >= -|q|
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Rule 3 0
I'm confused about this step in the final condition's proof:
|š(x) -š(x)| +|š(x) - š(x)| >=|š(x) -š(x) +š(x) - š(x)| = |š(x) - š(x)| since |q| >= q forall q
I can see how it's true by proving that |p| + |q| >= |p + q|, but that's not stated anywhere and I can't figure out how |q| >= q forall q is relevant.
Also, thanks a lot for making/showing a proof :D
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Minerule 2 0
i saw this before going to bed and i dreampt mojang actually added this and i was watching hbg highlights videos in the new update
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subiprime @lemmy.blahaj.zone
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