Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ , pastebin, or github (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)
Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
π Thread is locked until there's at least 100 2 star entries on the global leaderboard
I'm not fluent in Rust, but is this something like the C++ placement new? Presumably just declaring a table of Vecs won't automatically call the default constructor?
(Sorry for my total ignorance -- pointers to appropriate reading material appreciated)
Yes, it's a hash table. Did I pick a language with built in hash tables? Of course I didn't. Could I have used one of the many libraries implementing one? Sure. But the real question is, can we make do with stuffing things into a few static arrays at nearly zero memory and runtime cost? Yes!
In the spirit of Fred Brooks, itβll suffice here to show my data structures:
Took a while to figure out what part 2 was all about. Didn't have the energy to golf this one further today, so looking forward to seeing the other solutions!
import Data.Char
import Data.List
import Data.List.Split
import qualified Data.Vector as V
hash :: String -> Int
hash = foldl' (\a c -> ((a + ord c) * 17) `rem` 256) 0
hashmap :: [String] -> Int
hashmap = focus . V.toList . foldl' step (V.replicate 256 [])
where
focus = sum . zipWith focusBox [1 ..]
focusBox i = sum . zipWith (\j (_, z) -> i * j * z) [1 ..] . reverse
step boxes s =
let (label, op) = span isLetter s
i = hash label
in case op of
['-'] -> V.accum (flip filter) boxes [(i, (/= label) . fst)]
('=' : z) -> V.accum replace boxes [(i, (label, read z))]
replace ls (n, z) =
case findIndex ((== n) . fst) ls of
Just j ->
let (a, _ : b) = splitAt j ls
in a ++ (n, z) : b
Nothing -> (n, z) : ls
main = do
input <- splitOn "," . head . lines <$> readFile "input15"
print $ sum . map hash $ input
print $ hashmap input
0.248 line-seconds (sixth simplest so far after days 6, 2, 1, 4 and 9).
import collections
import re
from .solver import Solver
def _hash(string: str) -> int:
result = 0
for c in string:
result = (result + ord(c)) * 17 % 256
return result
def _assert_full_match(pattern: str, string: str):
m = re.fullmatch(pattern, string)
if not m:
raise RuntimeError(f'pattern {pattern} does not match {string}')
return m
class Day15(Solver):
input: list[str]
def __init__(self):
super().__init__(15)
def presolve(self, input: str):
self.input = input.rstrip().split(',')
def solve_first_star(self) -> int:
return sum(_hash(string) for string in self.input)
def solve_second_star(self) -> int:
boxes = [collections.OrderedDict() for _ in range(256)]
for instruction in self.input:
label, op, value = _assert_full_match(r'([a-z]+)([=-])(\d*)', instruction).groups()
box = boxes[_hash(label)]
match op:
case '-':
if label in box:
del box[label]
case '=':
box[label] = value
return sum((1 + box_idx) * (1 + lens_idx) * int(value)
for box_idx, box in enumerate(boxes)
for lens_idx, (_, value) in enumerate(box.items()))
Had to take a couple days off, but this was a nice one to come back to. Will have to find some time today to go back and do one or two of the 3 that I missed. I don't have much to say about this one - I had an idea almost immediately and it worked out without much struggle. There's probably some cleaner ways to write parts of this, but I'm not too disappointed with how it turned out.
This felt ... too simple. I think the hardest part of part two for me was reading comprehension. My errors were typically me not reading exactly was there.
Python
import re
import math
import argparse
import itertools
def int_hash(string:str) -> int:
hash = 0
for c in [*string]:
hash += ord(c)
hash *= 17
hash = hash % 256
return hash
class Instruction:
def __init__(self,string:str) -> None:
label,action,strength = re.split('([-=])',string)
self.label = label
self.action = action
if not strength:
strength = 0
self.strength = int(strength)
def __repr__(self) -> str:
return f"Instruction(l={self.label}, a={self.action}, s={self.strength})"
def __str__(self) -> str:
stren = str(self.strength if self.strength > 0 else '')
return f"{self.label}{self.action}{stren}"
class Lens:
def __init__(self,label:str,focal_length:int) -> None:
self.label:str = label
self.focal_length:int = focal_length
def __repr__(self) -> str:
return f"Lens(label:{self.label},focal_length:{self.focal_length})"
def __str__(self) -> str:
return f"[{self.label} {self.focal_length}]"
def main(line_list:str,part:int):
init_sequence = line_list.splitlines(keepends=False)[0].split(',')
sum = 0
focal_array = dict[int,list[Lens]]()
for i in range(0,256):
focal_array[i] = list[Lens]()
for s in init_sequence:
hash_value = int_hash(s)
sum += hash_value
# part 2 stuff
action = Instruction(s)
position = int_hash(action.label)
current_list = focal_array[position]
existing_lens = list(filter(lambda x:x.label == action.label,current_list))
if len(existing_lens) > 1:
raise Exception("multiple of same lens in box, what do?")
match action.action:
case '-':
if len(existing_lens) == 1:
current_list.remove(existing_lens[0])
case '=':
if len(existing_lens) == 0:
current_list.append(Lens(action.label,action.strength))
if len(existing_lens) == 1:
existing_lens[0].focal_length = action.strength
case _:
raise Exception("unknown action")
print(f"Part1: {sum}")
#print(focal_array)
sum2 = 0
for i,focal_box in focal_array.items():
for l,lens in enumerate(focal_box):
sum2 += ( (i+1) * (l+1) * lens.focal_length )
print(f"Part2: {sum2}")
if __name__ == "__main__":
parser = argparse.ArgumentParser(description="template for aoc solver")
parser.add_argument("-input",type=str)
parser.add_argument("-part",type=int)
args = parser.parse_args()
filename = args.input
if filename == None:
parser.print_help()
exit(1)
part = args.part
file = open(filename,'r')
main(file.read(),part)
file.close()
My whole solution can be expressed in just two words: Ordered HashTable
Total runtime: 0.068 line-seconds (40 LOC * 1.7 ms)
Puzzle rating: exceptionally confusing description 4/10
Code: cleaned up solution with types
Snippet:
proc getHash(s: string): int =
for c in s:
result = ((result + c.ord) * 17) mod 256
proc solve(lines: seq[string]): AOCSolution[int] =
var boxes: array[256, OrderedTable[string, int]]
for line in lines:
block p1:
result.part1 += line.getHash()
block p2:
if line.endsWith('-'):
var name = line.strip(leading=false, chars={'-'})
boxes[getHash(name)].del(name)
else:
let (name, _, value) = line.partition("=")
boxes[getHash(name)][name] = value[0].ord - '0'.ord
for bi, box in boxes:
if box.len < 1: continue
for vi, val in enumerate(box.values):
result.part2 += (bi+1) * (vi+1) * val