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How to roll 100:
- take 10 sided die, roll once
- take that number and multiply by 10
- roll 10 sided die again
- add that to the number from #2
- add 1 (otherwise it would be 0-99, not 1-100)
Alternatively:
Roll a percentile die and a d10 together. Done.
that's exactly what I said, also you'd still need to add 1 to make rolling 100 possible
Well, no, that's not exactly what you said. And rolling with a percentile die means you do not need to add anything. A result of 00 and 0 is the 100. And your way makes rolling a 1 impossible.
that is a different way of doing it I didn't think about but my method still works
to roll 1:
1st, 0 x 10 = 0
2nd, 0+0 = 0
add 1, 0 + 1 = 1to roll 100:
1st, 9 x 10 = 90
2nd, 90 + 9 = 99
add 1, 99 + 1 = 100that's the exact same except you count 0 AS 100 instead of adding 1
How do you get “1” like this?
I suppose you have to roll 10 to get to 100 = 0
But then what?
Then you switch to a system where you don't add the 1, interpreting 00 as 100
Modify step 2 so you subtract 1 from the roll first, then multiply by 10. That way if you roll a 1, the 10's digit becomes a 0.
Then you get 1 to 99
You get 100 when you roll 10 twice
(1d10 - 1) * 10 + 1d10 -> (10 - 1) * 10 + 10 = 9 * 10 + 10 = 90 + 10 = 100
Wouldn't that give you 11-100? l The Lowest number on a dice is 1, and 1×10 gives you 10.
The formula would have to be
((d10-1)×10)+d10=x≥90⟹y=(y+1)⟹z>1(d2)
So you'd still have to flip a coin on reaching a result of 90+ in order to know if you add a +1 or not as well or else you can't get 90 as a result either.
(This is assuming you have a d10 that's 1-10 btw and not 0-9!)
there's a 0 on the die
to roll 1:
1st, 0 x 10 = 0
2nd, 0+0 = 0
add 1, 0 + 1 = 1to roll 100:
1st, 9 x 10 = 90
2nd, 90 + 9 = 99
add 1, 99 + 1 = 100