There. You happy? This should help you divide 200 cm (2 metres, the width of the middle part) by the number of letters in Rindfleischetikettierungsüberwachungsaufgabenübertragungsgesetz.
The midde part actually has to be wider than 200cm, since there has to be a slot between the two wings while they aren't "stretched". I guess 200.5cm. So 200.5/63 = 3.18253968254 which is close to π. Interesting. πcm = 200.5cm/63 letters. Which means one letter in general is πcm. Based on that, we can say 1 meter is round about 31.8309886184 letters.
there has to be a slot between the two wings while they aren’t “streched”
Uh. Um. Your mum has to have a slot.
I don't understand what you're saying because I'm not a NERRRRRD* and you're AGAIN questioning my primary school teacher and you're using a lot of numbers like a NERRRRD so I shall disregard any further comments concerning the topic of the width and height of German blackboards.