What are some of your unpopular opinions in math? (not about math)
What are some of your unpopular opinions in math? (not about math)
For example: I don't believe in the axiom of choice nor in the continuum hypothesis.
Not stuff like "math is useless" or "people hate math because it's not well taught", those are opinions about math.
I'll start: exponentiation should be left-associative, which means a^b should mean b×b×...×b } a times.
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The exceptions including the number 1. Like it not being a prime number, or being 1 the result of any number to the 0 power. Or 0! equals 1.
I know 1 is a very special number, and I know these things are demonstrable, but something always feels off to me with these rules that include 1.
X^0 and 0! aren't actually special cases though, you can reach them logically from things which are obvious.
For X^0: you can get from X^(n) to X^(n-1) by dividing by X. That works for all n, so we can say for example that 2³ is 2⁴/2, which is 16/2 which is 8. Similarly, 2¹/2 is 2⁰, but it's also obviously 1.
The argument for 0! is basically the same. 3! is 1x2x3, and to go to 2! you divide it by 3. You can go from 1! to 0! by dividing 1 by 1.
In both cases the only thing which is special about 1 is that any number divided by itself is 1, just like any number subtracted from itself is 0
It's been a few years since my math lectures at university and I don't remember these two being explained so simple and straightforward (probably because I wasn't used to the syntax in math at the time) so thanks for that! This'll definitely stick in my brain for now
Or 0! equals 1.
x factorial is the number of ways you can arrange x different things. There's only one way to arrange zero things.
I could still debate the proposition that zero things can be arranged in any way.
That sounds like a philosophical position, not a mathematical one.
You are right but that is a dangerous proposal because math is just applied philosophy :)
0! = 1 isn't an exception.
Factorial is one of the solutions of the recurrence relationship f(x+1) = x * f(x). If one states that f(1) = 1, then it only follows from the recurrence that f(0) = 1 too, and in fact f(x) is undefined for negative integers, as it is with any function that has the property.
It would be more of an exception to say f(0) != 1, since it explicitly denies the rule, and instead would need some special case so that its defined in 0.