The Shell Scripting Tutorial: Parsing long command-line arguments with getopt
The Shell Scripting Tutorial: Parsing long command-line arguments with getopt

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Getopt - From the Shell Scripting Tutorial Tips

This is a little tutorial that I found in my search to learn how to use getopt
(mind: not getopts
, which is a completely different thing). I want to share it here because I find it refreshingly to the point. Just the main code block already tells almost the whole story:
#!/bin/bash # Set some default values: ALPHA=unset BETA=unset CHARLIE=unset DELTA=unset usage() { echo "Usage: alphabet [ -a | --alpha ] [ -b | --beta ] [ -c | --charlie CHARLIE ] [ -d | --delta DELTA ] filename(s)" exit 2 } PARSED_ARGUMENTS=$(getopt -a -n alphabet -o abc:d: --long alpha,bravo,charlie:,delta: -- "$@") VALID_ARGUMENTS=$? if [ "$VALID_ARGUMENTS" != "0" ]; then usage fi echo "PARSED_ARGUMENTS is $PARSED_ARGUMENTS" eval set -- "$PARSED_ARGUMENTS" while : do case "$1" in -a | --alpha) ALPHA=1 ; shift ;; -b | --beta) BETA=1 ; shift ;; -c | --charlie) CHARLIE="$2" ; shift 2 ;; -d | --delta) DELTA="$2" ; shift 2 ;; # -- means the end of the arguments; drop this, and break out of the while loop --) shift; break ;; # If invalid options were passed, then getopt should have reported an error, # which we checked as VALID_ARGUMENTS when getopt was called... *) echo "Unexpected option: $1 - this should not happen." usage ;; esac done echo "ALPHA : $ALPHA" echo "BETA : $BETA " echo "CHARLIE : $CHARLIE" echo "DELTA : $DELTA" echo "Parameters remaining are: $@"
Just be sure to correct the inadvertent mixing of beta
and bravo
.